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Amide bond formation
100%
adds a O=C[+] unit to an amine
100%
addition-elimination :N lp attacks C=O [equil] - tetrahedral intermed - proton shift [equil] - [-]O kicks back in elim gd LG on original acyl unit
100%
base to mop up H+ on the amine at the tetrahedral intermediate stage - dives equilibrium to rhs AND stops amine becoming protonated = would stop attacking carbonyl
100%
hydrolysing the acylating agent (has good leaving group)
100%
using aqueous base NaOH - biphasic - water with dcm - base in water layer neutralises charged intermediate acid generated by rxn, starting material and acylating agetn remain in organic phase
100%
Schotten Baumann rxn conditions
100%
DMAP and pyridine
100%
O acylation of alcohols
100%
Esters from alcohols and acylating agents
100%
Acid chloride, acid anhydrides, ethyl-esters, 4-nitrophenyl-esters, thio-ester, acyl-azide, acyl-imidazole
100%
Amine + Acid chloride aka [carbonyl w excellent LG like ester
0%

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Created Oct 2, 2019ReportNominate
Tags:Clickable Quiz, Med, Pt 2

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