Statement | True/False + Explanation |
Upon monobromination of 2,3,4-trimethylpentane, one alkyl bromide product results. | |
Upon monochlorination of 2,3,4-trimethylpentane, four unique alkyl chloride products result. | |
Bond dissociation energies are always negative. | |
High yields of a single organic haloalkane result upon radical bromination of 2-methylpentane. | |
Alkyl iodides may be prepared by free radical iodination. | |
High yields of a single organic haloalkane result upon chlorination of cyclohexane. | |
Monochlorination of 2-methylpropane yields only one chloroalkane product. | |
Two-headed arrows are used to illustrate arrow flow in the free radical halogenation mechanism. | |
The mechanism of free radical halogenation involves heterolytic cleavage reactions. | |
The propagation steps of the free radical halogenation mechanism sum up to the net reaction. | |
Free radical chlorination is not selective. | |
The termination step in free radical halogenation may be classified as homogenic bond formation. | |
Free radical chlorination is not selective. | |
Monochlorination of 2-methylpropane yields only one chloroalkane product. | |
High yields of a single organic haloalkane result upon chlorination of cyclohexane. | |
The termination step in free radical halogenation may be classified as homogenic bond formation. | |
Two-headed arrows are used to illustrate arrow flow in the free radical halogenation mechanism. | |
Bond dissociation energies are always negative. | |
The mechanism of free radical halogenation involves heterolytic cleavage reactions. | |
Upon monobromination of 2,3,4-trimethylpentane, one alkyl bromide product results. | |
Upon monochlorination of 2,3,4-trimethylpentane, four unique alkyl chloride products result. | |
High yields of a single organic haloalkane result upon radical bromination of 2-methylpentane. | |
Alkyl iodides may be prepared by free radical iodination. | |
The propagation steps of the free radical halogenation mechanism sum up to the net reaction. | |