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Can you name the three-digit number that isn't divisible by the given number?
created by
puckett86
Enter a number in the box below
Correctly named numbers will show up below
Answers do not have to be guessed in order
Some wrong answers will appear in red
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PLAY GAME
Enter number:
0
/19 numbers correct
06:00
Show Missed Answers
Divisible By...
Odd One Out
Possible Numbers
2
116, 134, 233, 494, 888
3
102, 311, 462, 591, 708
4
240, 544, 716, 876, 954
5
235, 285, 371, 480, 890
6
318, 498, 678, 838, 942
7
191, 231, 511, 665, 875
8
112, 458, 656, 744, 992
9
279, 297, 651, 693, 711
10
200, 510, 560, 650, 655
11
155, 198, 550, 781, 891
Divisible By...
Odd One Out
Possible Numbers
12
156, 300, 408, 660, 880
13
273, 338, 416, 542, 585
14
322, 466, 532, 686, 742
15
405, 555, 615, 775, 960
16
176, 624, 672, 720, 958
17
204, 306, 469, 561, 833
18
162, 288, 754, 828, 864
19
399, 489, 608, 779, 836
20
350, 400, 520, 740, 860
2
350, 400, 520, 740, 860
3
350, 400, 520, 740, 860
4
350, 400, 520, 740, 860
5
350, 400, 520, 740, 860
6
350, 400, 520, 740, 860
7
350, 400, 520, 740, 860
8
350, 400, 520, 740, 860
9
350, 400, 520, 740, 860
10
350, 400, 520, 740, 860
11
350, 400, 520, 740, 860
12
350, 400, 520, 740, 860
13
350, 400, 520, 740, 860
14
350, 400, 520, 740, 860
15
350, 400, 520, 740, 860
16
350, 400, 520, 740, 860
17
350, 400, 520, 740, 860
18
350, 400, 520, 740, 860
19
350, 400, 520, 740, 860
20
350, 400, 520, 740, 860
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1 to 100 in Hexadecimal
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There are
44 comments
for this game.
(Warning: comments may contain spoilers)
Odd Number Out Quiz
by
puckett86
Created May 4, 2011 in
Science
Featured May 23, 2011
Game Plays 31,645
Report a Mistake
Tags
Numbers Quizzes
Math Quizzes
wrong
right
odd
algebra
possible
factor
Editor Pick
three
digit
Archived comments:
show them
sproutcm
:
May 5th, 2011 at 05:53 GMT
8 points
@puckett Wow, those large primes were hard, but that was perfectly timed and a great challenge.
Tahnan
:
May 5th, 2011 at 09:48 GMT
22 points
It's a good thing there's such an easy test for divisibility by 13 and 19, namely "divide the number by 13 or 19 and see if there's a remainder"....
Flick
:
May 5th, 2011 at 11:06 GMT
15 points
@Tahnan: an easy(ish) test for divisibility by 13 is to remove the last digit and multiply it by 4, than add this to the remaining two-digit number. If the answer is divisible by 13, then so is the original number... and now brace yourself for other tests of divisibility rules ! @ Puckett86: I gave this game my un-divided attention. Great stuff.
AdmiralMaxtreme
:
May 5th, 2011 at 11:43 GMT
7 points
Great game. One problem I noticed was that the incorrect answer for 16 for some reason shows up in the answer box for 2.
puckett86
:
May 5th, 2011 at 12:36 GMT
8 points
@AdmiralMaxtreme I've fixed it. Thanks. Still getting used to this new "Wrong answer" feature.
rockgolf
:
May 5th, 2011 at 16:28 GMT
30 points
Other (simple) divisibility rules:
2: Last digit is even.
3: The sum of the digits is divisible by 3.
4: Ignore everything but the last two digits. If they're divisible by 4, the whole number is.
5: Last digit is 0 or 5.
6: Sum of the digits is divisible by 3
and
last digit is even.
9: Sum of the digits is divisible by 9.
10: Last digit is zero.
12: Sum of the digits divisible by 3. Last 2 digits divisible by 4.
15: Sum of the digits divisible by 3. Last digit 0 or 5.
18: Sum of the digits divisible by 9. Last digit even.
20: Last digit is zero. Second last digit is even.
Sensational game,
puckett
. Exceedingly simple but brilliant premise. Must have been tricky not getting any overlap. Five orbs & nominated.
MikeN
:
May 5th, 2011 at 19:57 GMT
3 points
How did people feel about the time? I though it cold use more entries for that much time.
WyvernSabres
:
May 5th, 2011 at 20:49 GMT
6 points
Worrying. Ten people (so far) couldn't tell which was the non-multiple of 2.
lucyzoe
:
May 6th, 2011 at 01:38 GMT
1 point
@puckett86, how about finding some more editor's picks?
puckett86
:
May 6th, 2011 at 02:49 GMT
4 points
@lucyzoe What do you mean? Finding more picks in Just For Fun? If so, do you have suggestions? I thought I make plenty of picks. It may not appear that way since many of them have been published.
Pyrophorus
:
May 8th, 2011 at 06:33 GMT
6 points
There's another rule for 11, but only for 3-digit numbers (so it works on this quiz): add the first and last digits. If the sum is equal to the middle digit, or if the sum is equal to 11, then the 3-digit number is divisible by 11. The more general form of this rule is given at http://www2.semo.edu/philosophy/mathclub/divisibility.htm
This page (http://home.egge.net/~savory/maths1.htm) has more rules for other prime numbers, including another more general rule for 11
Me_TakeItOrLeave
:
May 16th, 2011 at 01:51 GMT
9 points
On behalf of those who managed to get 2 5 and 10 wrong; Why isn't 1 included? ;)
Game published: May 23rd, 2011 at 04:03 GMT
Comment below threshold:
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triviafanpatriot
:
May 23rd, 2011 at 04:20 GMT
-8 points
I like this quiz, but there should be less time to prevent people from just using a calculator.
puckett86
:
May 23rd, 2011 at 04:44 GMT
10 points
@triviafanpatriot I've lowered the time from 7 to 6 minutes, but I don't think there's anything I can really do to prevent people from cheating.
On a related note, for those of you who are wondering how to do this without cheating, check out rockgolf's post (and others) in the archived comments for some divisibility rules.
godpaul25
:
May 23rd, 2011 at 04:56 GMT
23 points
even if you dont have the rules for divisibility memorized (which i don't past 10) you can simply figure out if the first number is divisible, and if so, just subtract that # from the next # and see if the difference is divisible. Making it a smaller number is easier and faster. I.e. for #13: 273 is divisible by 13 (21 times) so subtract 273 from the next number, 338 = 65. Is 65 divisible by 13? yes 5 times. So subtract 338 from 416 = 78 (yes, 6x) etc until you find one that isn't. Just simplifies it esp if you can subtract in your head faster than you divide.
diplomatt
:
May 23rd, 2011 at 06:47 GMT
4 points
I started rushing and missed the 8 question. What a goof. Slow and steady wins the race, my friends.
woowoo682
:
May 23rd, 2011 at 07:06 GMT
8 points
those damn 17's were always the worst part of the multiplication tables for me
x_Deggerz_x
:
May 23rd, 2011 at 08:06 GMT
5 points
Must admit. This has been the most frustrating quiz...and thats what I like from a quiz :) GOOD JOB
druhutch
:
May 23rd, 2011 at 09:27 GMT
7 points
I love how you've embraced the new 'wrong answer' format. However, I was told there would be no math. (Then again I'm pretty okay with getting only half of them right. In my high school that would've qualified me for the "mathletes")
TL333s
:
May 23rd, 2011 at 12:30 GMT
2 points
Wrong answers in Sporcle? What?
Comment below threshold:
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sargeanthr
:
May 23rd, 2011 at 12:39 GMT
-31 points
there are many ways for a number to be the odd one out. e.g. number 6, the odd one out is 942 because it is the only one that ends in 2
Pogues
:
May 23rd, 2011 at 14:36 GMT
2 points
The time seems to be perfect. I managed to, with some made up math rules...apparently, get through every question in the time allotted. Now if I just managed to get them all correct....hmph. Fun quiz.
PAisGreat
:
May 23rd, 2011 at 14:52 GMT
2 points
I love math quizzes! Usually I just can't type fast enough, but this one gave me enough time to type & it was mentally refreshing.
burnsy
:
May 23rd, 2011 at 15:21 GMT
5 points
"Nine, nine, nine. That crazy number nine. Times any number you can find, it all comes back to nine." God, I loved Square One. God, I was a nerd.
heynostradamus
:
May 23rd, 2011 at 16:53 GMT
7 points
Good quiz. I wouldn't change the time to make sure people don't use a calculator. If people want to be dbags and cheat, fair enough. It doesn't really affect me. What satisfaction could you possibly get out of using a calculator? It's just like any other quiz on here. You could use google. But what's the point then?
MoRichBowler300
:
May 23rd, 2011 at 17:56 GMT
5 points
godpaul25, there is a divisibility rule for 11. Alternatively subtract and add the numbers that you are trying to see is a multiple of 11. If the answer adds up to 0 or a multiple of 11, then it works. For example lets take the number 889724. 8 - 8 + 9 - 7 + 2 - 4 = 0, so 889,724 is divisible by 11.
godpaul26
:
May 23rd, 2011 at 19:14 GMT
0 points
Yes I know there is. I just don't have it memorized is what I said
Comment below threshold:
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vcgfdfgd
:
May 23rd, 2011 at 21:00 GMT
-5 points
way to much time
Comment below threshold:
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angiegirl
:
May 23rd, 2011 at 23:31 GMT
-7 points
i don't get this quiz...
Comment below threshold:
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jangles
:
May 24th, 2011 at 01:43 GMT
[Comment deleted by admins]
sluh138
:
May 24th, 2011 at 02:01 GMT
2 points
Great quiz...
squiggsy
:
May 24th, 2011 at 16:53 GMT
-4 points
All numbers can be divided by all numbers except no number can be divided by zero. I'd change the description and/or title to include the word evenly. 233/2 = 116.5. It can be done, just not evenly. Good quiz and format.
puckett86
:
May 24th, 2011 at 19:37 GMT
4 points
@squiggsy: x is divisible by y if x/y is an integer. So the "evenly" part is understood when you say "divisible".
PlumpMenofHaddam
:
May 25th, 2011 at 00:41 GMT
3 points
Great topic, and good selection of numbers. I do think the rules should be a bit more clearly stated -- it's not clear that one would only get one shot at each question. (I'm fine with the format, but the intro should be a bit more clear on that point.)
PK9
:
May 25th, 2011 at 02:07 GMT
3 points
Most of the answers for the multiples of three (6, 12, 15, 18) fail the test for being multiples of three, greatly simplifying each test. 651 (for 9) is the only one that is a multiple of three, but not a multiple of its clue.
Shwoo
:
May 26th, 2011 at 13:19 GMT
3 points
Stupid primes. I wonder if there is a divisibility rule for 17 or 13. I only know the ones for 1-11, excepting 7.
squiggsy
:
May 30th, 2011 at 16:37 GMT
-1 points
@puckett86 That may be true, but nowhere in this quiz does it say integer. It only says number.
puckett86
:
Jun 2nd, 2011 at 20:07 GMT
5 points
@squiggsy It doesn't have to say integer. x/y needs to be an integer, but x/y isn't given. I just give you x and y, and yes they happen to be integers, but they don't have to be. Example: 2e is divisible by e; because 2e/e is 2, an integer, but neither 2e nor e are integers. It is all stated correctly.
Comment below threshold:
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squiggsy
:
Jun 8th, 2011 at 17:05 GMT
-8 points
You can blindly defend you thoughts all you want, but 116, 134, 233, 494 and 888 are all divisible by 2. Watch: 233/2 = 116.5. Explain to me how 233 is indivisble by 2? By saying indivisble, you are stating it can't be done. It is very clear and, to use your word, implied that it can be done.
puckett86
:
Jun 10th, 2011 at 03:02 GMT
5 points
@squiggsy 233 is not divisible by 2 because there is a remainder (of 1) when you calculate 233/2. The term "evenly divisible" is archaic, and is now simply "divisible".
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